Question

A pack of 52 cards is dealt to four players . What is the probability that the first player gets 2 ace

Answer 1

2/52

1/26 is the answer

Answer 2

We can simplify this to the probably of four aces being distributed 1 each to 4 people, where any allocation of those four aces is possible.   Pr = (number of allocations which are 1 each) / (total number of possible allocations)  Number of allocations which are 1 each = 4! (i.e. how many different ways can you allocate "seat" 4 aces at each of 4 players)  Total number of possible allocations = 4^4 (each ace can go any of four ways if there is no constraint that they have to go to separate people)  So: Pr = 3/32  Hope this helps