A paper is in the form of a rectangle PQRS in which PQ=10cm QR= 7cm.Two semi circular portions with qr and ps as diameter are cut off ,find the area of the remaining part.
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PQ=RS=10cm ( In a rectangle all opposite sides are
QR=PS=7cm equal)
Area of rectangle = l×b = 10×7 = 70sqcm
Area of two semi circles = 2×pie rsquare/2
=22/7×7/2×7/2
=77/2 = 38.5sqcm
Area of the remaining part = 70 - 38.5 = 32.5cmsq
QR=PS=7cm equal)
Area of rectangle = l×b = 10×7 = 70sqcm
Area of two semi circles = 2×pie rsquare/2
=22/7×7/2×7/2
=77/2 = 38.5sqcm
Area of the remaining part = 70 - 38.5 = 32.5cmsq
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