Question

A parallel plate capacitor has square plates of side 5 cm and separated by a distance of 1 mm.

calculate the capacitance of this capacitor . (The value of

o



= 8.85 x 10-12 Nm2 C

-2

)​

Answer 1

Answer:

can't understand this question

Answer 2

Answer:

A square-shaped parallel plate capacitor with an area is $0.0025m^{2}$ and separated by a distance of 1 mm the capacitance is  $22*10^{-12}F$

Explanation:

• The parallel plate capacitor is two parallel plates that are connected across a battery when the plates are charged an electric field will induce between them.

• The CAPACITANCE is the ability to store electric charge within the capacitor

• For a parallel plate capacitor with an area $A$ separated by a distance $d$ in free space, the capacitance is

                                  $C=\frac{\varepsilon _0\ A}{d}$

                         

from the question, we have

the side length of the square plate $l=5cm=0.05m$

area of square plate $A=l^{2}=0.0025m^{2}$

distance between two parallel plates $d=1mm=0.001m$

capacitance in free space $C=\frac{8.8*10^{-12} *0.0025}{0.001} =22*10^{-12} F$