A parallel plate capacitor is charged to a certain voltage.
Now, if the dielectric material (with dielectric constant k) is
removed then the
(a) capacitance increases by a factor of k
(b) electric field reduces by a factor k
(c) voltage across the capacitor decreases by a factor k
(d) None of these
Answers
Answer:
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Explanation:
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Explanation:
Initial capacitance c=
d
kε
0
A
When the system is isolated, charge (Q) present on it is constant.
Now, when dielectric is removed C=
d
ε
0
A
⇒ C decreases by a factor of K.
We know that Q=C×V
As C decreases by factor of K and Q remains constant, V increases by a factor of K