A parallel plate capacitor of plate area A and plates separation distance d is charged by applying a potential V_(0) between the plates. The dielectric constant of the medium between the plates is K. What is the uniform electric field E between the plates of the capacitor ?
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Explanation:
Answer
after inserting slab
newcapacitanceC
′
=KC=
d
Kϵ
o
A
newpotentialdifferenceV
′
=
K
V
newelectricfieldE
′
=
d
V
′
=
kd
V
newchargeQ
′
C
′
=
d
ϵ
o
AV
work=final−initial
=
2
1
C
′
V
′
−
2
1
CV
2
2
1
(KC)=(1−
K
1
)
[ω]=
2d
ϵ
o
AV
2
(1−
K
1
)
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