A parallelogram has sides 30 m and 14 m and one
of its diagonal is 40 m long. Then find its area
Answers
Answered by
0
Answer:
Area is : 336
Answered by
0
Answer :
336
Explanation:
let ABCD be the given parallelogram
area of parallelogram ABCD = 2 x (area of triangle ABC)
now a = 30m, b = 14m and c = 40m
s=1/2 x (30+14+40) = 42
Area of triangle ABC = [s(s−a)(s−b)(s−c)]‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√
= [42(12)(28)(2)]‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√
= 168sq m
area of parallelogram ABCD = 2 x 168 = 336 sq m
Hope it’s helpful and you can understand...
336
Explanation:
let ABCD be the given parallelogram
area of parallelogram ABCD = 2 x (area of triangle ABC)
now a = 30m, b = 14m and c = 40m
s=1/2 x (30+14+40) = 42
Area of triangle ABC = [s(s−a)(s−b)(s−c)]‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√
= [42(12)(28)(2)]‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√
= 168sq m
area of parallelogram ABCD = 2 x 168 = 336 sq m
Hope it’s helpful and you can understand...
Similar questions