Question

A parallelogram has vertices P (1,4) ; Q(7,11) ; R(a,4) and S(1;-3) . find the value of a.

Answer 1

HERE IS THE ANSWER MATE

Answer 2

draw PQRS is the required parallelogarm,O is the midpt of both the diagonals,

midpoint of PR = midpoint of  QS

so by midpoint formula,

o(x,y)= (7+1/2,  11-3/2)

        =(4,4)

0(x,y)=(x1 +x2/2,     y1+y2/2  )

        =(1+a/2 , 4+4/2)

        =(1+a/2  ,  4)

4=1+a/2

8=1+a

a=7

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