A particle 1 of mass m initially at A is at rest the radius of circular path is 1 m . the particle collides at bottom with an other particle 2 of same mass m . the distance travelled by the particle before coming to the rest is
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Answered by
19
Answer:
I explained in above ,if any doubt msg me
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NILESH0KR:
thanx for complete explanation
Answered by
6
Answer:
Explanation:
1st part is frictionless same as general fall case and second part is with friction so by putting v2- u2=2as we will get the answer.
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