A particle having the same charge as of electron moves in a circular path of radius 0.5 cm under the influence of a magnetic field of 0.5 T. If an electric field of 100 V/m makes it to move in a straight path, then the mass of the particle is (given charge of electron = 1.6 × 10⁻¹⁹ C)
(A) 9.1 × 10⁻³¹ kg (B) 1.6 × 10⁻²⁷ kg
(C) 1.6 × 10⁻¹⁹ kg (D) 2.0 × 10⁻²⁴ kg
Answers
Answered by
1
D. will be correct answers
Mark the answer brainliests please
Attachments:
Answered by
1
The mass of particle is 2*10^-24kg
Given
Radius =0.5 cm
Magnetic field=0.5T
Whenever a particle is in magnetic field and moves in circle centripetal force acts on that particle
Charge given=1.6*10^-19C
Mv^2/R= qvb
Therefore mv =qRb
Also from electric force
qE= qvB
q gets cancel from both sides
v=E/B
M*E/B=qrb
m=qrb^2/E
=1.6*10^-19*0.5*10^-2*0.5*0.5/100
=1.6*125*10^-3*10^-4*10^-19
=200*10^-26 kg
=2*10^-24 kg
ie option (d)
Similar questions