Science, asked by bhanu211999, 5 months ago

A particle hits the ground with a velocity of
50 m/s. If the coefficient of restitution is 0.6,
the velocity of rebound is ------- m/s.​

Answers

Answered by snehitha9
0

Answer:

I think you have to give the photo or any picture

Answered by nitinkumar9lm
0

Answer:

The velocity of rebound is -30 m/s .

Explanation:

  • The elasticity of the collision is measured by the value of the coefficient of restitution.
  • For the perfect elastic collision, the value of the coefficient of restitution is 1.

The formula for the velocity of rebound is:

V_{rb} =-(e\times V)

where e is the value of the coefficient of restitution

           V is the velocity of the particle on hitting the ground.

It is given that e=0.6 and V=50 m/s.

The velocity of rebound, V_{rb} =-(0.6\times 50) m/s

                                               =-30 m/s

So, the velocity of rebound is -30 m/s. (negative sign is due to the change in the direction).

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