Question

A particle is acted upon by four forces simultaneously:

1.30N due east

2.20N due north

3.50N due west and

4.40N due south

Find

Find the resultant force on the particle

Answer 1

The resultant force is 10N and particle move in east

Answer 2

Answer:The resultant force on the particle is $R= 20\sqrt{2}$.

Explanation:

Given that,

Force $F_{1}= 30 N$ due east

Force $F_{2}= 20 N$ due north

Force $F_{1}= 30 N$ due West

Force $F_{1}= 30 N$ due south

We know that,

The effective force along west

$F_{w}= 50\ N-30\ N$

$F_{w}= 20 N$

The effective force along south

$F_{s}= 40\ N-20\ N$

$F_{s}=20 N$

The resultant force is

$R = \sqrt{F_{w}^{2}+F_{s}^{2}}$

$R= \sqrt{20^{2}+20^{2}}$

$R= 20\sqrt{2}$

Hence, The resultant force on the particle is $R= 20\sqrt{2}$.