Math, asked by sree912, 1 year ago

a particle is moves 10 m in the east direction and then 5m to west direction.the magnitude of displacement covered by the particle​

Answers

Answered by NiteshKhatri
3

Answer:

5m

Step-by-step explanation:

Magnitude is5m because both are in opposite direction

So 10-5=5m

Answered by ranikumari4878
1

Answer:

5 m

Step-by-step explanation:

Let's assume that the particle is initially at a point A.

From there, particle move to east direction by 10 m and then 5 m to east direction from there, that means, just opposite direction of east.

Displacement of the particle is shortest distance from its initial to final position.

since the particle here move only on one straight line.

so the displacement of the particle= 10 m - 5 m

                                                          = 5 m

so, the particle is just 5 m away from it's initial position

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