A particle is moving along a circular path with a constant speed of 10 ms⁻¹. What is the magnitude of the change in velocity of the particle, when it moves through an angle of 60º⁺ around the centre of the circle?
(A) 10√3 m/s (B) 0
(C) 10√2 m/s (D) 10 m/s
Answers
Given:
A particle is moving along a circular path with a constant speed of 10 meter per second
To Find:
Magnitude of the change in the velocity when it moves through an ange of 60 degree around the center of circle.
Solution:
The particle is moving along a circular path with a constant velocity of 10 meter per second.
When a object is rotating along a circle , It has 2 accelerations
Tangential acceleration and Radial acceleration
Radial acceleration is due to the centrifugal force which helps the particle to hold its position so as to rotate in a circle of constant radius.
As mentioned in the question itself, particle is moving with constant velocity, Hence tangential acceleration is equals to 0 .
It is not mentioned it the question that the angular velocity is constant.
Hence we will assume that angular velocity is constant.
The change in velocity of the particle is 0