Question

A particle is moving eastward with
a velocity of 5 m/s. In 10 seconds,
the velocity changes to 5 m/s
northwards. Find the average
acceleration of the particle in this
time interval.​

Answer 1

Answer:

Please Give Me A Brainliest.

Here by the formula

$a = (v - \: u) \div t$

Thus ,

here u=5m/s

v=5m/s

t=10 seconds

a=?

Hence,

a=(v-u)÷t

a=(5-5)÷10

Explanation:

Thus the acceleration is of

$10 \: \frac{m}{ {s}^{2} }$