Question

A particle is moving with a uniform acceleration. Its velocity after 5 s is 25 ms and after 8s is 34 ms. The distance travelled in the 12th second is
a) 50m
b) 55m
c) 40.5m
d) 44.5m
Anyone answer this question with full step by step explanation.​

Answer 1

ANSWER

V = u + at

After 5s

25 = u + 5a ——(1)

After 8s

34 = u + 8a ——(2)

Subtract equation (1) from equation (2)

34 - 25 = u + 8a - u - 5a

9 = 3a

a = 3 m/s^2

Substitute a = 3m/s^2 in equation (1)

25 = u + 5*3

u = 10 m/s

Distance travelled in 12th second

S = u + a(n - 1/2)

S = 10 + 3*(12 - 1/2)

S = 44.5m

Distance travelled in 12th second is 44.5m