A particle is projected at 60° with horizontal with a kinetic energy K.What is the kinetic energy when it makes angle 30°?
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let u be the initial velocity.
∴ initial kinetic energy is K = (1/2)mu²
at the maximum height velocity is u cos60 = (u/2)
∴ kinetic energy at the maximum height is KE=(1/2)m(u/2)²
=(1/4)k
∴ initial kinetic energy is K = (1/2)mu²
at the maximum height velocity is u cos60 = (u/2)
∴ kinetic energy at the maximum height is KE=(1/2)m(u/2)²
=(1/4)k
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