Question

a particle is projected obliquely into air with velocity of 20m/s at an angle of elevation of 45° neglecting air resistance the equation of motion is

Answer 1

Heya user,

The Equation of the trajectory of a projectile is given by :--->

----> y = ( tan θ )x - [ g x² / { 2( u cos θ )² } ]

Substituting the values, cos 45 = 1/√2 and tan 45 = 1;

we get our equation --> y = x - gx²/400 => 400y = x - 9.8x²

Hence, after rearranging, our equation becomes --> 
----------------> 49x² - 5x + 2000y = 0; <---- The desired result