Physics, asked by mayor72, 21 days ago

A particle is projected up from the ground with a velocity of 147m/s at an angle of projection 30° with the horizontal. The horizontal range is use g=9.8ms^(-2)
a)200m
b)275.6m
c)1909.6m
d)300m​

Answers

Answered by ashishshanavas
2

Answer:

Explanation:

R=v^2 sin2x/g

=21609*\sqrt{3}/20

=1909.6

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