Question

A particle is projected vertically up from the top of a tower

Answer 1

Answer:

A particle is projected vertically up from the top of a tower with velocity 10m/s It reaches the ground in 5 sec. ... Since particle take s 5s to reach the ground from point of projection.

Explanation:

When we project the the ball from tower then it's

intial velocity = u = 10m/s

final velocity = v = 0m/s (when it reaches maximum height)

acceleration due to gravity = a = g = -9.8m/s²(here - sign because object is moving opposite direction of acceleration)

distance = s1 = ?

v²-u² = 2as1

s1 = v²-u²/2a

s1 = (0)²-(10)²/2(9.8)

s1 = 0-100/-19.6

s1 = -100/-19.6

s1 = 5.102m

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When we project the ball from tower then it reaches maximum hieght then it will be in rest at that moment.Then it starts to fall down

intial velocity = u = 0m/s

acceleration due to gravity = a = g = 9.8m/s²

time = t = 5s

distance = s2 = ?

s2 = ut + at²/2

s2 = 0(5) + 9.8(5)²

s2 = 0 + 9.8(25)

s2 = 245m

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so total distance traveled by an object

S3 = s1 + s2

S3 = 245 + 5.102

S3 = 250.102 m

so total distance covered by an object is 250.102 meter

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If you want to find the height of the tower then ,

h = S2 - s1

h = 245 - 5.012

h = 239.898 meter

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