Question

. A particle is projected with a velocity of 20 ms - at an angle
of 60° to the horizontal. The particle hits the horizontal plane
again during its journey. What will be the time of impact?
(a) 3.53 s.
(b) 2.4 s
(C) 1.7 s
(d) 1s​

Answer 1

Answer:

Velocity at max height =20cos60

=10 m/s.

i.e.,

using momentum conservation

10×2m=m×v

⇒v=20 m/s.

Explanation: