Physics, asked by njjagan8548, 11 months ago

A particle is projected with a velocity v=3i-j+2k

Answers

Answered by ItSdHrUvSiNgH
2

Explanation:

\Huge\underline{\underline{\sf Answer}} \\ v = 3i - j + 2k \\  |v|  =  \sqrt{ {3}^{2} + ( { - 1})^{2}  +   {2}^{2} }  \\  |v|  =  \sqrt{9 + 1 + 4}  \\  |v|  =  \sqrt{14}

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