A particle is pushed
along a horizontal surface in such a way that it starts with velocity of 12m/s,its velocity decreases at rate of 0.5m/s.Find the time it will take to come at rest.
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We wantv=0
V=u +at
0= 12+-(0.5)t
-12=-(0.5)t
12=0.5t
5t=120
T=24 sec
V=u +at
0= 12+-(0.5)t
-12=-(0.5)t
12=0.5t
5t=120
T=24 sec
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