Question

A particle is throwm upward with a velocity of 50 m/s find the velocity at highest point of its journey

Answer 1

it's velocity at highest point of its journey will be zero. Then it start coming towards earth.

Answer 2

Explanation:

To find: Pair of corresponding angles

Solution: In ΔPOQ and ΔROS

PO=RO (each 4 cm)

OQ=OS (each 4 cm)

PQ=RS (each 5 cm)

ΔPOQ≅ΔROS(By SSS cong. rule)

∴ corresponding ∠s are

∠P=∠R

∠POQ=∠ROS

∠Q=∠S.To find: Pair of corresponding angles

Solution: In ΔPOQ and ΔROS

PO=RO (each 4 cm)

OQ=OS (each 4 cm)

PQ=RS (each 5 cm)

ΔPOQ≅ΔROS(By SSS cong. rule)

∴ corresponding ∠s are

∠P=∠R

∠POQ=∠ROS

∠Q=∠S.To find: Pair of corresponding angles

Solution: In ΔPOQ and ΔROS

PO=RO (each 4 cm)

OQ=OS (each 4 cm)

PQ=RS (each 5 cm)

ΔPOQ≅ΔROS(By SSS cong. rule)

∴ corresponding ∠s are

∠P=∠R

∠POQ=∠ROS

∠Q=∠S.To find: Pair of corresponding angles

Solution: In ΔPOQ and ΔROS

PO=RO (each 4 cm)

OQ=OS (each 4 cm)

PQ=RS (each 5 cm)

ΔPOQ≅ΔROS(By SSS cong. rule)

∴ corresponding ∠s are

∠P=∠R

∠POQ=∠ROS

∠Q=∠S.