Question

A particle is thrown upward with a velocity of 50 m/s. It passes the point A at 3 sec and 7 sec after the projection. If height of point A (in m) from the point ofhprojection is h. Findh/100​

Answer 1

Explanation:

u=50m/s

g=−10m/s2

The velocity at the highest point will be zero

Thus, v=0

Height can be calculated as,

v2−u2=2gs

0−2500=−20s

s=125m

Time can be calculated as,

v=u+gt

0=50+(−10)t

t=5sec