Question

a particle is thrown with a speed u at an angle theta with the vertical. when the particle makes an angle Ф with the vertical, its speed changes to v.c

Answer 1

Hii dear,

◆ Answer -

v = u.cosθ/cosФ

◆ Explanation -

Let u & v be the speed of the particle when it makes angle θ and Ф with the vertical respectively.

In projectile motion, horizontal component of velocity always remains same.

Horizontal velocity at θ = Horizontal velocity at Ф

u.cosθ = v.cosФ

v = u.cosθ/cosФ

Therefore, speed of the particle changes to u.cosθ/cosФ .

Thanks dear..

Answer 2

Answer:

the required answer will be

V = ucos theta.sec∅

hope it helped you ✨