Question

A particle moves 3m north, 4m east, and finally 6m south. Calculate its distance travel and its displacement

Answer 1

Answer:

Explanation:

Solution,

Here, we have

Three directions of particle,

North = 3 m

East = 4 m

South = 6 m

To Find,

Distance and displacement

Here,

Distance traveled = 3 + 4 + 6

Distance traveled = 13 m.

Hence, the distance traveled is 13 m.

Here, we know that,

Displacement - Displacement is the distance in a particular direction.

So,

= (Displacement)²

= 32 + 42

= 9 + 16

= 25

Hence, the displacement is 25 m.

Answer 2

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Question

⋄ A particle moves 3m north, 4m east, and finally 6m south. Calculate its distance travel and its displacement.

_______________________________

Given:-

Distance covered by particles in three different directions.

North=3m

East=4m

South =6m.

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To Find :-

Distance and Displacement covered by particle.

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Solution :-

Distance travelled by particules = 3m+4m+6m=13m.

∴The distance travelled by particle is 13m.

Now,

Displacement is the shortest path between two points.

Displacement = AD

By using Pythagoras theorem

AD² = AE²+ED²

AD² = 4²+3²

AD² = 25

AD = √25

AD=5 m

∴ The displacement of the particle is 5m.

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