Question

a particle moves along a straight line such that its position x changes with time as: 12x = 4t3-15t2 +12t +6, where x is in m and t in sec.find the distance covered by it at the end of t = 2s.

Answer 1

Explanation:

12x = 4t^3 - 15t^2 + 12t + 6

differentiate --------

12x = 12t^2 - 15t + 12

put t = 2 sec

12x = 12 × 2^2 - 15× 2 + 12

12x = 48 - 30 + 12

12x = 18 + 12

12x = 30

x = 30/12

x = 5/2 Ans.