a particle moves along x-axis in such a way that itsx coordinates
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Hi_______
it have no need to differentiate it .
hope u understand my logic.
option a is correct .
a=dv/dt=d/dt(dx/dt).
x=4-2t+t^2
differentiate
v=2t-2
again differentiate
a=2
now find the slope of line in all option
u see only 1 option give to it.
it have no need to differentiate it .
hope u understand my logic.
option a is correct .
a=dv/dt=d/dt(dx/dt).
x=4-2t+t^2
differentiate
v=2t-2
again differentiate
a=2
now find the slope of line in all option
u see only 1 option give to it.
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gowtham16:
in v-t graph line doesnot represent the displacement
V=x/t if u plot graph between vand t then what u get
In velocity time graph slope of the line gives acceleration.
X it is
Displacement
the slope is acceleration
and the area made by the line with x axis gives displacement or to be accurate distance
Ya dear it is 1/x represents , a=v/t then u get a
Ya u gotta my point right now
Ok i do it another way
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