Physics, asked by makwanaanil8032, 1 year ago

A particle moves from a point (-2i+5j) to (4j+3k) when a force of (4i+3j)n is applied .How much work has been done by the force??

Answers

Answered by srikanth1903
3

Answer:

Work done by the force is 5 Joules.

Explanation:

Force on the particle, F = 4i + 3 j

A particle moves from a point x₁ = (-2i + 5j) to x₂ = (4j + 3k)

Work done by the force is given by :

we know that, i.i=j.j=k.k=1

So,

W = 5 Joules.

Hence, the work done by the force is 5 Joules.

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Answered by amarraj79
1

Answer:

R1=-2i+5j;R2=4i+3j

Displacement verctor

R=R2-R1

=6i-2j

F=(4i+3j)N

Work done W=FdotproductR

=(4i+3j).(6i-2j)

=24-6=18jule

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