A particle moves from a point (-2i+5j) to (4j+3k) when a force of (4i+3j)n is applied .How much work has been done by the force??
Answers
Answered by
3
Answer:
Work done by the force is 5 Joules.
Explanation:
Force on the particle, F = 4i + 3 j
A particle moves from a point x₁ = (-2i + 5j) to x₂ = (4j + 3k)
Work done by the force is given by :
we know that, i.i=j.j=k.k=1
So,
W = 5 Joules.
Hence, the work done by the force is 5 Joules.
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Answered by
1
Answer:
R1=-2i+5j;R2=4i+3j
Displacement verctor
R=R2-R1
=6i-2j
F=(4i+3j)N
Work done W=FdotproductR
=(4i+3j).(6i-2j)
=24-6=18jule
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