Question

A particle moves from point A to point D on the given path as shown in the figure. The displacement of the particle will be​

Answer 1

Answer:

where is that figure which are you talking

Answer 2

Answer:

triangle ABO, ∠AOB=θ

AB is the displacement of the particle.

Using cosθ=

2(AO)(BO)

AO

2

+BO

2

−AB

2

Or cosθ=

2R

2

R

2

+R

2

−AB

2

We get AB

2

=2R

2

−2R

2

cosθ

Or AB

2

=2R

2

(1−cosθ)=2R

2

×2sin

2

(

2

θ

)

⟹ AB=2Rsin

2

θ

Distance covered by the particle d=Rθ

Thus ratio of distance and displacement

AB

d

=

2sin

2

θ

θ

Thank you