Math, asked by Srishti304, 1 year ago

A particle moves in a circle with angular velocity "omega" as shown, about center O. Find the instantaneous angular velocity about point P.

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Answered by Saumya10600

Since in that dt time it covers half the angle rotated about point O, it's angular velocity is "omega"/2. Hope this helps you:)

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Chinmay007: Hey, Thanks for your response. Will you tell me if it's angle QOR in place of angle POR- according to exterior angle theorem?

Saumya10600: I didn't understand your question. What's the problem?

Chinmay007: IDk a reason why you've written this : angleQPO +anglePQO =anglePOR?

Chinmay007: instead of anglePOR in the RHS (am i correct?)

Chinmay007: *angleQOR

Saumya10600: Oh I am sorry. My mistake. It should be angleQOR. Writing error.

Chinmay007: yeah! never mind

Chinmay007: the real thing u wanna say is that omega us dtheta/dt & so it will depend on the angle taken in account.ryt?

Saumya10600: yes. That's the essence of it.

Chinmay007: alright!

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