Question

A particle moves with constant acceleration to 2m/s in X direction the distance travelled in 5th second is 19m calculate the distance travelled after 5 second​

Answer 1

Explanation:

sn= u+a(n-1/2)

19=u+2(5-1/2)

19=u+2(9/2)

19=u+9

u=10

s=ut+1/2att

=10(5)+1/2(2*25)

=50+25

=75