Question

A particle moving in a circle of radius R =3m with an angular speed of 2 radian per second in clockwise direction as given in diagram. The acceleration (in m/s^2)of particle at point P is

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Answer 1

Answer:

now solve for Cos and sin compoments and add vectors and u will get ur amswer

Answer 2

Answer:

As the angular speed of the particle is 2 rad/s hence we can say ω=2rad/s.

For the particle 2 types of acceleration is responsible which are centripetal(at) and tangential(at).

Of which the tangential acceleration at any point will be 0 as there is no component of time in the given angular speed.

Thus, only centrepetal acceleration ac will work which is, ac=ω*2r=3*2*2 = 12m/s.

According to the figure there will be 2 components one cos and other sin which will be (ac)cos60(-i) + (ac)sin60(-j).

Thus the position of the particle will be P = -6i - 6√3j.