Physics, asked by ammulukasturi, 10 months ago

A particle moving with a velocity equal to 0.4 m/s is subjected to an acceleration of 0.15 m/^2 for 2 seconds in a direction at right angles to the direction of motion . The magnitude of the final velocity
A. 0.3m/s^2
B. 0.4m/s^2
C. 0.5m/s^2
D. 0.7m/s^2

Answers

Answered by rishabhp12
2

Answer:

0.7

Explanation:

use the formula

v = u +at

Answered by arvindsinghmalik1791
1

Answer:

Explanation:12×3/4€43÷5

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