A particle moving with uniform acceleration along
X-axis crosses the points x = 2 m and x = 7 m with
velocities 5 ms-1 and 15 ms-1 respectively. The
velocity with which it crosses point x = 3 m is
(1) root65 ms-1
(2) 10 ms-1
(3)root35
Answers
Answered by
1
let initial velocity is u and uniform acceleration is a.
at x = 2m, v = 5m/s
using formula, v² = u² + 2as
⇒(5)² = u² + 2a(2)
⇒25 = u² + 4a..........(1)
at x = 7m , v = 15m/s
so, (15)² = u² + 2a(7)
⇒225 = u² + 14a .........(2)
from equations (1) and (2),
we get, 225 - 25 = 14a - 4a
⇒200 = 10a
⇒a = 20m/s²
and u² = 225 - 14 × 20 = 225 - 280 = -55 m/s
now, velocity at x = 3m, v² = (-55) + 2(20)(3)
= -55 + 120
= 65
so, v = √65 m/s
hence, option (1) is correct choice.
Answered by
0
(1) root65 ms-1
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