Question

A particle of mass 0.01 kg executing shm has 0.04. If the frequency of vibration is 32hz;find its angular velocity,maximum velocity and energy.

Answer 1

Hey dear,

You didn't give the graph. I'll add it with an image attachment.

◆ Answer-

T = 0.3142 s

◆ Solution-

# Given-

m = 0.01 kg

# Solution-

We are given with graph if force vs displacement. Force constant is calculated by slope of graph -

k = F / x

k = [8 - (-8)] / [2 - (-2)]

k = 16 / 4 = 4 N/m

Angular velocity is given by -

ω = √(k/m)

ω = √(4/0.01)

ω = 20 m/s

Time period of SHM -

T = 2π / ω

T = 2×3.142 / 20

T = 0.3142 s

Therefore, time period of SHM is 0.3142 s.

Hope this helps you...