Question

A particle of mass 80 units is moving with a uniform speed v=4 sqrt 2 units in XY plane, along a line y=x+5. The magnitude of the angular momentum of the particle about the origin is

Answer 1

Answer:

y = x + 4 given. x - y + 4 = 0 Perpendicular distance from origin r = 4/√(2) = 2√(2) Now angular momentum = mvr = 5 × 3√(2) × 2 √(2) = 60

Answer 2

Answer:

v×m×r

2×3root 2× cos 45

so it is 60

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