Question

A particle of mass m moving in the x direction with speed 2v is hit by another particle of mass 2m moving in the y direction with speed v. If the collision is perfectly inelastic, the percentage loss in the energy during the collision is close to

Answer 1

use the formula of loss in K.E=1/2 {m1m2/(m1+m2)} ×{( V1-V2)^2 } × (1-e^2)

where V1 and V2 are in vector form.

e=0(for perfectly inelastic collision)

Initial K.E=1/2 m (2v)^2 +1/2 (2m) v^2

%loss =(K.E loss/Initial K.E)×100

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