Question

A particle reduces its speed from 54 km/h to rest in 10 seconds. The acceleration of the particle is ______​

Answer 1

Answer:

-5.4m/s

Explanation:

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Answer 2

Answer:

Given :-

• initial velocity, u = 54 km/h $=\cancel{54}\times \frac{5}{\cancel{18}} \\ = 3 \times 5 = 15 m/s$
• final velocity, v = 0 km/h = $0\times \frac{5}{18} = 0 m/s$
• time, t = 10 seconds

To find :-

• The acceleration of the particle

Solution :-

$\boxed{\green{v = u + at}}$

$0 = 54 + a(10) \\ 0 = 54 +10a \\ 10a = 0 - 54 \\ 10a = - 54 \\ a = \frac{ - 54}{10} \\ \underline{\underline{\boxed{\purple{a = - 5.4}}}}$

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