Physics, asked by riyadash57, 5 hours ago

A particle reduces its speed from 54 km/h to rest in 10 seconds. The acceleration of the particle is ______​

Answers

Answered by gouravgupta65
3

Answer:

-5.4m/s

Explanation:

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Answered by manasvi61
0

Answer:

Given :-

  • initial velocity, u = 54 km/h  =\cancel{54}\times  \frac{5}{\cancel{18}} \\ = 3 \times 5 = 15 m/s
  • final velocity, v = 0 km/h =  0\times  \frac{5}{18} = 0 m/s
  • time, t = 10 seconds

To find :-

  • The acceleration of the particle

Solution :-

\boxed{\green{v = u + at}}

0 = 54 + a(10) \\ 0 = 54 +10a \\ 10a = 0 - 54 \\ 10a =  - 54 \\ a =  \frac{ - 54}{10}  \\ \underline{\underline{\boxed{\purple{a =  - 5.4}}}}

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