A particle thrown vertically upwards. Its velocity at half height is 10 m/s. The maximum height attaimed by it is
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- Let maximum height be H
- From the formula, v
- 2
- =u
- 2
- −2gs
- (10)
- 2
- =u
- 2
- −2gH/2=u
- 2
- −gH ........(1)
- For attaining maximum height, v=0
- 0=u
- 2
- −2gH⇒u
- 2
- =2gH
- Putting the value of u
- 2
- in (1),
- 100=2gH−gH=gH
- H=
- g
- 100
- =
- 10
- 100
- =10metre
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