Question

a particle travels 10m in first 5 seconds and 10m in next 3 seconds. Assuming constant acceleration, what is the distance travelled in next 2 second

Answer 1

Answer:
1. 8.3 m
Explanation:
Particle travels 10m in first 5 seconds
Using equation of motion S = ut + at 2
10 = 5u +
Multiply both sides with 8
80 = 40u + 100a ———————(1)
Particle travels 10m in next 3s (or) it travels 20m in first 8s
Again, using equation of motion S = ut + at 2
20 = 8u +
Multiply both sides with 5
100 = 40u + 160a ——————(2)
Subtract equation (2) from equation (1)
80 − 100 = 40u + 100a − 40u − 160a
−20 = − 60a
a = ms −2
Substitute value of a in equation (1)
80 = 40u +
40u = 80 −
40u =
u = ms −1
We got acceleration = ms −2 and initial velocity (u) =
ms −1
————————
Distance travelled in first 10s
S = ut + at 2
S = +
S = m
Distance travelled in next 2s = Distance travelled in first 10s - Distance travelled in first 8s
= m − 20m
= m
= 8.3m