A particle travels with speed 50 m/s from point (3,-7) in the direction 7i-24j find the position vector after 3 secs
jasmine3552:
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(7^2 + 24^2)^(1/2) = 25
50/25 = 2
3*2 = 6
6*7 = 42
6*24 = 144
3 + 42 = 45
- 7 + 144 = 137
(i,j) = (45,137)
50/25 = 2
3*2 = 6
6*7 = 42
6*24 = 144
3 + 42 = 45
- 7 + 144 = 137
(i,j) = (45,137)
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Answer:39i^ -137j^
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