Question

A particle under goes two displacements represented vertically as 2i^-3j^+5k^and i^+3j^-4k^.what is net displacement? Find it's magnitude. ​

Answer 1

Explanation:

38. O

000-2

5. Find the number of terms in each of the following APs :

() 7,13, 19,..., 205

bax by the time her

6. Check whether - 150 is a term of the AP: 11.8.5,2...

(m) 18,15

.13,...,-41

years old

Here, the am

third, fourth bir

To find the total a

each of the 21

would be a tedio

This would be

term

9. If the 3rd and the 9th terms of an AP are 4 and

8 respectively, which termos

zero?

We con

12

Chapter 1). te

the positive i

you guess h

And then

M. Which term of the AP:3, 15, 27, 39, ... will be 132 more than its 54th term

12. Two APs have the same common difference. The difference between their 100

100. what is the difference between their 1000th terms?

13. How many three-digit numbers are divisible by 7?

14. How many multiples of 4 lie between 10 and 250? 12 -

8. For what value of n, are the nth terms of two apa

Adding

4. Which term of the AP: 3.8. 13. 18... is 78?

Retse on her

7. Find the 31st term of an AP whose 11th term is 38 and the 16th term is 73.

8. An AP consists of 50 terms of which 3rd term is 12 and the last term is 106.

10. The 17th term of an AP exceeds its 10th term by 7. Find the common differenz

Answer 2

Solution :-

• As total displacement vector is the sum of vectors of 2 individual displacements.

• After getting resultant displacement vector we can find the magnitude of it.

Total displacement = (2i^ - 3j^ + 5k^) + (i^ + 3j^ - 4k^)

⇒ (2i^ - 3j^ + 5k^) + (i^ + 3j^ - 4k^)

⇒ 2i^ - 3j^ + 5k^ + i^ + 3j^ - 4k^

⇒ 3i^ + k^

The magnitude of net displacement is :

$\bf{\rightarrow\:\:\sqrt{(3)^2+(1)^2} }$

$\bf{\rightarrow\:\:\sqrt{9+1} }$

$\bf{\rightarrow\:\:\sqrt{10} }$

Final Answer :-

The magnitude of net displacement is √10

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