a particle was at rest from 9 a.m. it movedat a uniform speed 10km/hr from 9.30 a.m. to 10 a.m. find the average speed between (a) 9.00 a.m.and 10.00 a.m., (b) 9.15 a.m. and 10.00 a.m. (ans. 5km/h, 6.67km/h)
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Given conditions ⇒
Speed of the Particles = 10 km/hr.
As per as the Question, we need to find the Average speed of the Particles between 9 am to 10 am.
∴ Total time = 1 hrs.
Speed of the Particles between 9 to 9:30 am = 0
∴ Distance covered by the Particles in 30 minutes = 10 × 0.5
= 5 km.
Average speed = Total Distance/Total time.
∴ = 5 × 1
= 5 km/hr.
Hence, the average speed of the Particles is 5 km/hr.
___________________________
(b). Distance covered in 30 minutes = 5 km.
Total time taken by it = 45 minutes.
= 45/60 hrs.
= 3/4 hrs.
∴ Average Speed = 5/(3/4)
= 20/3
= 6.67 km/hr.
Hence, the average speed of the Particles is 6.67 km/hr.
Hope it helps. :-)
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