Question

a particle was at rest from 9 a.m. it movedat a uniform speed 10km/hr from 9.30 a.m. to 10 a.m. find the average speed between (a) 9.00 a.m.and 10.00 a.m., (b) 9.15 a.m. and 10.00 a.m. (ans. 5km/h, 6.67km/h)
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Answer 1

Just see the pic and if my ans. Is correct then you can mark as brillian...... but if my ans. Doesn't match then don't mark me as loser....

Answer 2

Given conditions ⇒

Speed of the Particles = 10 km/hr.  

As per as the Question, we need to find the Average speed of the Particles between 9 am to 10 am.  

∴ Total time = 1 hrs.  

Speed of the Particles between 9 to 9:30 am = 0  

∴ Distance covered by the Particles in 30 minutes = 10 × 0.5

= 5 km.  

Average speed = Total Distance/Total time.  

∴  = 5 × 1  

   = 5 km/hr.  

Hence, the average speed of the Particles is 5 km/hr.  

___________________________

(b). Distance covered in 30 minutes = 5 km.  

Total time taken by it = 45 minutes.  

= 45/60 hrs.  

= 3/4 hrs.  

∴ Average Speed = 5/(3/4)

   = 20/3  

   = 6.67 km/hr.  

Hence, the average speed of the Particles is 6.67 km/hr.  

Hope it helps. :-)

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nice dp