Question

xy/y-x=110, yz/z-y=132, zx/z+x=60/11

Answer 1

Answer:

Step-by-step explanation:

First make Inverse of the question we get

y-x/xy=1/110 ; z-y/yz=1/132 ; z+x/zx=11/60

by furter evalauating we get

y/xy-x/xy=1/110 ∴ 1/x-1/y=1/110.

z/yz-y/yz=1/132 ∴ 1/y-1/z=1/132.

z/zx+x/zx=11/60 ∴1/x+1/z=11/60

adding equation 2 and 3 we get

1/x+1/y=1/132+11/60.........new equation

adding equation 1 nd new equation we get

1/x+1/x+1/y-1/y =1/132+1/110+11/60

2/x=10+242+12/1320

x=1320 × 2/264 =10

∴ x=10 putting the values we get  y=11 z=12