A particular population of chickens has a frequency for the dominant allele as 0.70 and a frequency for the recessive allele as 0.30. Which expression is the correct way to calculate the frequency of individuals that are heterozygous?
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It is one of the applications of Hardy Weinberg Equilibrium.
You can directly use the formula,
(p+q)^{2} =p ^{2} + q ^{2} + 2pq.
Where p is the frequency of dominant allele
q is the frequency of recessive allele
2pq is the frequency of heterozygous allele.
Hope it helps you
You can directly use the formula,
(p+q)^{2} =p ^{2} + q ^{2} + 2pq.
Where p is the frequency of dominant allele
q is the frequency of recessive allele
2pq is the frequency of heterozygous allele.
Hope it helps you
PPPP68:
No problem.. Feel free to ask me any question you are facing trouble with
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