A partide is projected horizontally with speed 10 m/s from a building of height 20m at t= 0. Then find out radius of curvature at t = 1 sec. O 202m O 10/2m O 10 am O 10m
Answers
Answered by
1
Answer:
Correct option is
C
2.8m
v
x
=10cos60
o
=5m/s
v
y
=10cos30
o
=5
3
m/s
Velocity after t=1 sec
v
x
=5m/s
v
y
=∣(5
3
−10)∣m/s=10−5
3
a
n
=
R
v
2
⇒
a
n
v
x
2
+v
y
2
=
10cosθ
25+100+75−100
3
tanθ=
5
10−5
3
=2−
3
⇒θ=15
o
R=
10cos15
100(2−
3
)
=2.8m
Answered by
0
Answer:
tere ko nahi pata kya jo puch rha hai
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