Question

A path 4 m wide runs along inside a square park of side 80 m.Find the area of the path.Also find the cost of cementing the path at the rate of Rs.350 per 6 m sq.

Answer 1

Let ABCD be the square park.
And EFGH be the inner part except the path.

Area of ABCD = 80*80=6400sqm

One side of EFGH =
$80 - (4 \times 2) \\ 80 - 8 = 72$
Area of EFGH = 72*72 = 5184sqm

Therefore, area of the path =
$area \: of \: abcd \: - area \: of \: efgh \\ \\ 6400 - 5184 = 1216sqm$


Cost for cementing the path at the rate of 350 per 6sqm
(1216÷6)*350= ₹70933.331

Answer 2

Answer:

Step-by-step explanation: