A path and s 3m wide is running along the inside of the bouqndary of a rectangular filed 116m by 76 m how much money needed to gravelvthe path at rs 42.50 per
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heya frnd!
here's ur answer...
given:-
length of the rectangular field=116m
breadth of the rectangular field=76m
area of the rectangular field=l×b
=116×76
=8816m²
length of the path=116-(3+3)
=116-6
=110 {as 3m wide path runs inside the field}
breadth of the field=76-(3+3)
=76-6
=70m
area of the field excluding path=110×70
=7700m²
area of the path=8816-7700
=1116m²
hence, the area of the path is 1116m²
hope this helps..!
here's ur answer...
given:-
length of the rectangular field=116m
breadth of the rectangular field=76m
area of the rectangular field=l×b
=116×76
=8816m²
length of the path=116-(3+3)
=116-6
=110 {as 3m wide path runs inside the field}
breadth of the field=76-(3+3)
=76-6
=70m
area of the field excluding path=110×70
=7700m²
area of the path=8816-7700
=1116m²
hence, the area of the path is 1116m²
hope this helps..!
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