.A path of uniform width runs around and outside a square plot of side 25 m. If the area of the path is 216 m2 then its width is (0) 2 m (2) 4 m (3) 3 m (4) 8 m
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Answer:
Let the width of the path be x.
∴ length of the rectangular field and path =2x+30
and breadth =2x+24
Area of rectangular field =(30×24)
=720
Area of the rectangular field and path =(2x+30)(2x+24)
Now,
(2x+30)(2x+24)−720=360
⇒4x2+48x+60x+720−720=360
⇒4x2+108x−360=0
⇒x2+27x−90=0
⇒x2+30x−3x−90=0
⇒x(x+30)−3(x+30)=0
⇒(x+30)(x−3)=0
⇒x=−30 and x=3
Negative value is not valid,
∴ Width is 3 cm
Explanation:
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